(問 5/5)
(x+a)2 =x2+2ax+a2
(x+a)2 =x2+2ax+a2
正解です、おめでとう。
(x-5y)2 =x2 -5x-5xy +25y2
=x2 +(-5-5)xy +25y2
=x2 -10xy +25y2
=x2 +(-5-5)xy +25y2
=x2 -10xy +25y2
| x | -5y | |
| x | x2 | -5xy |
| -5y | -5xy | 25y2 |
=x2 -10xy +25y2
合格です。おめでとう、
次問へ進む
| x | -5y | |
| x | x2 | -5xy |
| -5y | -5xy | 25y2 |